Matematyka
$f\left(x\right) =$ |
$\dfrac{{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{x}$
Note: Your input has been rewritten/simplified. |
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$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$ |
$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\dfrac{{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{x}\right)}}$ $=\dfrac{\class{steps-node}{\cssId{steps-node-4}{x{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)\right)}}}}-\class{steps-node}{\cssId{steps-node-6}{\class{steps-node}{\cssId{steps-node-5}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x\right)}}{\cdot}{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}}}{\class{steps-node}{\cssId{steps-node-2}{{x}^{2}}}}$ $=\dfrac{\left(\class{steps-node}{\cssId{steps-node-8}{\class{steps-node}{\cssId{steps-node-7}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\mathrm{e}}^{x}\right)}}{\cdot}\sin\left(2x\right)}}+\class{steps-node}{\cssId{steps-node-10}{{\mathrm{e}}^{x}{\cdot}\class{steps-node}{\cssId{steps-node-9}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sin\left(2x\right)\right)}}}}\right){\cdot}x-\class{steps-node}{\cssId{steps-node-11}{1}}{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{{x}^{2}}$ $=\dfrac{x{\cdot}\left(\class{steps-node}{\cssId{steps-node-12}{{\mathrm{e}}^{x}}}{\cdot}\sin\left(2x\right)+\class{steps-node}{\cssId{steps-node-13}{\cos\left(2x\right)}}{\cdot}\class{steps-node}{\cssId{steps-node-14}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(2x\right)}}{\cdot}{\mathrm{e}}^{x}\right)-{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{{x}^{2}}$ $=\dfrac{x{\cdot}\left({\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)+\class{steps-node}{\cssId{steps-node-15}{2}}{\mathrm{e}}^{x}{\cdot}\cos\left(2x\right)\right)-{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{{x}^{2}}$ Wynik alternatywny: $=\dfrac{{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{x}-\dfrac{{\mathrm{e}}^{x}{\cdot}\sin\left(2x\right)}{{x}^{2}}+\dfrac{2{\mathrm{e}}^{x}{\cdot}\cos\left(2x\right)}{x}$ |